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Differential EquationsSuperchallengeSecond-Order Linear Equations

Second-Order Linear Equations · Superchallenge problem

The oscillator y′′+by′+(1+b24)y=0y'' + by' + \left(1 + \dfrac{b^2}{4}\right)y = 0, b>0b > 0, has energy E=12y′2+12(1+b24)y2E = \tfrac12 y'^2 + \tfrac12\left(1 + \tfrac{b^2}{4}\right)y^2. Between any two consecutive local maxima of yy it loses exactly three quarters of its energy. Find bb.