MathCastle
Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+5y′+4y=0y''+5y'+4y=0 with y(0)=1y(0)=1, y′(0)=−6y'(0)=-6. Find the time at which the mass crosses equilibrium (y=0y=0).