Differential EquationsChallengeSecond-Order Linear Equations ShareSecond-Order Linear Equations · Challenge problemA mass obeys y′′+ω2y=0y'' + \omega^2 y = 0y′′+ω2y=0 with y(0)=0y(0) = 0y(0)=0 and y′(0)=1y'(0) = 1y′(0)=1, where ω>0\omega > 0ω>0. Find the smallest ω\omegaω for which y(1)=y(2)y(1) = y(2)y(1)=y(2).Check Show answer Walk through it step by step Practice more like this Review this concept