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Differential EquationsChallengeSecond-Order Linear Equations

Second-Order Linear Equations · Challenge problem

The function y1=e−2tcos⁡3ty_1 = e^{-2t}\cos 3t solves y′′+by′+cy=0y'' + by' + cy = 0 for certain constants b,cb, c. Another solution y2y_2 of the same equation has y2(0)=0y_2(0) = 0, and the Wronskian W=y1y2′−y2y1′W = y_1y_2' - y_2y_1' equals 66 at t=0t = 0. Find y2(π6)y_2\left(\dfrac{\pi}{6}\right).