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Differential EquationsHardNonhomogeneous Equations & Resonance

Nonhomogeneous Equations & Resonance · Hard problem

For y′′+2y′+5y=cos⁡(ωt)y''+2y'+5y=\cos(\omega t) with ω>0\omega>0, the steady-state response lags the forcing by a phase angle φ\varphi with tan⁡φ=2ω5−ω2\tan\varphi=\dfrac{2\omega}{5-\omega^2}. Find ω\omega for which the phase lag is exactly π4\dfrac\pi4.