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Differential EquationsHardLaplace II: Steps, Impulses & Convolution

Laplace II: Steps, Impulses & Convolution · Hard problem

A circuit obeys y′+y=f(t)y'+y=f(t), y(0)=0y(0)=0, where ff is a triangular pulse: f(t)=tf(t)=t for 0≤t<20\le t<2, f(t)=4−tf(t)=4-t for 2≤t<42\le t<4, and f(t)=0f(t)=0 for t≥4t\ge4. Use the Laplace transform to find y(6)y(6).