Differential EquationsSuperchallengeLaplace Transforms ShareLaplace Transforms · Superchallenge problemUsing the power series of sint\sin\sqrt{t}sint and L{ta}=Γ(a+1)sa+1\mathcal{L}\{t^{a}\} = \dfrac{\Gamma(a+1)}{s^{a+1}}L{ta}=sa+1Γ(a+1) term by term, evaluate ∫0∞e−tsint dt\displaystyle\int_0^\infty e^{-t}\sin\sqrt{t}\,dt∫0∞e−tsintdt.Check Show answer Walk through it step by step Practice more like this Review this concept