Differential EquationsEasyLaplace Transforms ShareLaplace Transforms · Easy problemUsing L{sinkt}=ks2+k2\mathcal{L}\{\sin kt\} = \dfrac{k}{s^2 + k^2}L{sinkt}=s2+k2k, find L{sin3t}\mathcal{L}\{\sin 3t\}L{sin3t} evaluated at s=1s = 1s=1.Check Show answer Walk through it step by step Practice more like this Review this concept