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Differential EquationsSuperchallengeFrobenius & Special Functions

Frobenius & Special Functions · Superchallenge problem

Chebyshev's equation (1−x2)y′′−xy′+9y=0(1 - x^2)y'' - xy' + 9y = 0 has a regular singular point at x=1x = 1 with indicial roots 00 and 12\tfrac12. Let y=∑n≥0an(1−x)n+1/2y = \displaystyle\sum_{n\ge0}a_n(1 - x)^{n + 1/2}, with a0=1a_0 = 1, be the Frobenius solution about x=1x = 1 for the root 12\tfrac12; it converges for ∣1−x∣<2|1 - x| < 2. Compute y(0)y(0). Express your answer in simplest radical form.