MathCastle
Differential EquationsSuperchallengeFrobenius & Special Functions

Frobenius & Special Functions · Superchallenge problem

Let y(x)=∑n≥0anxny(x) = \sum_{n\ge0}a_nx^n be the Frobenius solution, with a0=1a_0 = 1, of x(1−x)y′′+(1−2x)y′−14y=0x(1-x)y'' + (1 - 2x)y' - \tfrac14y = 0 about its regular singular point x=0x = 0. The series converges for ∣x∣<1|x| < 1 and y(x)→∞y(x) \to \infty as x→1−x \to 1^-. Compute lim⁡x→1−y(x)ln⁡11−x\displaystyle\lim_{x\to1^-}\frac{y(x)}{\ln\frac{1}{1-x}}.