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Differential EquationsSuperchallengeFrobenius & Special Functions

Frobenius & Special Functions · Superchallenge problem

The hypergeometric equation z(1−z)y′′+(32−2z)y′−14y=0z(1 - z)y'' + \left(\tfrac32 - 2z\right)y' - \tfrac14y = 0 has indicial roots 00 and −12-\tfrac12 at z=0z = 0. Let y(z)=∑n≥0anzny(z) = \sum_{n\ge0}a_nz^n be the Frobenius solution for r=0r = 0 with a0=1a_0 = 1. Compute y ⁣(34)y\!\left(\tfrac34\right).