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Differential EquationsHardFrobenius & Special Functions

Frobenius & Special Functions · Hard problem

Solve x2y′′−2xy′+2y=x3exx^2y'' - 2xy' + 2y = x^3e^x for x>0x > 0 with y(1)=0y(1) = 0 and y′(1)=0y'(1) = 0, and compute y(2)y(2).