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Differential EquationsEasyFrobenius & Special Functions

Frobenius & Special Functions · Easy problem

For 2xy′′+y′−y=02xy'' + y' - y = 0, a Frobenius series y=∑n≥0anxn+ry = \sum_{n\ge0} a_n x^{n+r} leads to the recurrence (n+r)(2n+2r−1) an=an−1(n+r)(2n+2r-1)\,a_n = a_{n-1} for n≥1n \ge 1. Take the root r=12r = \tfrac12 and a0=1a_0 = 1. Compute a2a_2. Express your answer as a common fraction.