Frobenius & Special Functions · Easy problem

The Cauchy–Euler equation $x^2y'' - 3xy' + 4y = 0$ has the solutions $y_1 = x^2$ and $y_2 = x^2\ln x$ for $x > 0$. Compute their Wronskian $W = y_1y_2' - y_2y_1'$ at $x = 2$.