Frobenius & Special Functions · Easy problem

The Cauchy–Euler equation $x^2y'' + 5xy' + 4y = 0$ has general solution $y = c_1x^{-2} + c_2x^{-2}\ln x$ for $x > 0$. For the solution with $y(1) = 1$ and $y'(1) = 0$, find $c_2$.