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Differential EquationsChallengeFrobenius & Special Functions

Frobenius & Special Functions · Challenge problem

A Cauchy–Euler equation x2y′′+pxy′+qy=0x^2y'' + pxy' + qy = 0 has the particular solutions y=x2y=x^2 and y=x−3y=x^{-3} (so its indicial roots are 22 and −3-3). For the solution with y(1)=5y(1) = 5 and y′(1)=1y'(1) = 1, find y(2)y(2). Express your answer as a common fraction.