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Differential EquationsChallengeFrobenius & Special Functions

Frobenius & Special Functions · Challenge problem

The equation x2y′′+5xy′+13y=0x^2y'' + 5xy' + 13y = 0 (for x>0x>0) has complex indicial roots −2±3i-2 \pm 3i. The solution with y(1)=0y(1) = 0, y′(1)=2y'(1) = 2 is zero at x=1x=1. Find the next value of x>1x > 1 where it is zero again. Give an exact answer.