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Differential EquationsHardBoundary Values & Fourier Series

Boundary Values & Fourier Series · Hard problem

Find the Fourier sine series of f(x)=x(π−x)f(x) = x(\pi - x) on [0,π][0, \pi], and evaluate it at x=π2x = \dfrac\pi2 to find ∑k=0∞(−1)k(2k+1)3=1−127+1125−⋯\displaystyle\sum_{k=0}^{\infty}\dfrac{(-1)^k}{(2k+1)^3} = 1 - \dfrac1{27} + \dfrac1{125} - \cdots.