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Differential EquationsEasyBoundary Values & Fourier Series

Boundary Values & Fourier Series · Easy problem

Find the Fourier coefficient b2=1π∫−ππxsin⁡2x dxb_2 = \dfrac1\pi\displaystyle\int_{-\pi}^{\pi} x\sin 2x\,dx of f(x)=xf(x) = x on [−π,π][-\pi, \pi].