Differential EquationsMediumExact Equations & Substitutions ShareExact Equations & Substitutions · Medium problemSolve y′=y2+2xyx2y' = \dfrac{y^2 + 2xy}{x^2}y′=x2y2+2xy with y(1)=1y(1) = 1y(1)=1, and find y (32)y\!\left(\dfrac32\right)y(23).Check Show answer Walk through it step by step Practice more like this Review this concept