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Differential EquationsChallengeExact Equations & Substitutions

Exact Equations & Substitutions · Challenge problem

The equation (x2+y2+y) dx−x dy=0(x^2 + y^2 + y)\,dx - x\,dy = 0 becomes exact after dividing by x2+y2x^2 + y^2. Use this to find the solution with y(1)=0y(1) = 0, and compute y ⁣(1+π4)y\!\left(1 + \dfrac{\pi}{4}\right).