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Differential EquationsChallengeExact Equations & Substitutions

Exact Equations & Substitutions · Challenge problem

Consider y′=x+y−3x−y−1y' = \dfrac{x + y - 3}{x - y - 1} with y(3)=1y(3) = 1. Followed to the right, the solution curve rises until its tangent line becomes vertical, where the solution y(x)y(x) ends. Find the value of yy at that point.