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Differential EquationsChallengeExact Equations & Substitutions

Exact Equations & Substitutions · Challenge problem

The Riccati equation y′=y2−2x2y' = y^2 - \dfrac{2}{x^2} has the particular solution y1=1xy_1 = \dfrac1x. Use the substitution y=1x+uy = \dfrac1x + u to solve it with y(1)=2y(1) = 2 for x>0x > 0, and find y ⁣(12)y\!\left(\dfrac12\right).