Differential EquationsChallengeExact Equations & Substitutions ShareExact Equations & Substitutions · Challenge problemThe solution of y′=y+y3y' = y + y^3y′=y+y3 with y(0)=1y(0) = 1y(0)=1 exists on 0≤x<b0 \le x < b0≤x<b and tends to infinity as x→bx \to bx→b. Find bbb.Check Show answer Walk through it step by step Practice more like this Review this concept