CalculusSuperchallenge ShareCalculus · Superchallenge problemLet y=arctan (1+x2−1x)y=\arctan\!\left(\dfrac{\sqrt{1+x^2}-1}{x}\right)y=arctan(x1+x2−1) for x>0x>0x>0. Find dydx\dfrac{dy}{dx}dxdy at x=1x=1x=1.Check Show answer Walk through it step by step Practice more like this