CalculusChallenge ShareCalculus · Challenge problemFor x>0x>0x>0 let f(x)=arctan(2x)−arctan(x)f(x)=\arctan(2x)-\arctan(x)f(x)=arctan(2x)−arctan(x). The function fff rises and then falls. At what value of xxx is fff largest?Check Show answer Walk through it step by step Practice more like this