CalculusSuperchallengeNon-Elementary Integration ShareNon-Elementary Integration · Superchallenge problemUsing ∫0π/2sin2p−1xcos2q−1x dx=Γ(p)Γ(q)2Γ(p+q)\displaystyle\int_0^{\pi/2}\sin^{2p-1}x\cos^{2q-1}x\,dx=\dfrac{\Gamma(p)\Gamma(q)}{2\Gamma(p+q)}∫0π/2sin2p−1xcos2q−1xdx=2Γ(p+q)Γ(p)Γ(q), find ∫0π/2sin9xcosx dx∫0π/2sin5xcos5x dx\dfrac{\displaystyle\int_0^{\pi/2}\sin^9x\cos x\,dx}{\displaystyle\int_0^{\pi/2}\sin^5x\cos^5x\,dx}∫0π/2sin5xcos5xdx∫0π/2sin9xcosxdx without evaluating either integral numerically.Check Show answer Walk through it step by step Practice more like this Review this concept