CalculusMediumNon-Elementary Integration ShareNon-Elementary Integration · Medium problemWallis' formula for even powers is ∫0π/2sin2nx dx=(2n−1)(2n−3)⋯1(2n)(2n−2)⋯2⋅π2\displaystyle\int_0^{\pi/2}\sin^{2n}x\,dx=\dfrac{(2n-1)(2n-3)\cdots1}{(2n)(2n-2)\cdots2}\cdot\dfrac\pi2∫0π/2sin2nxdx=(2n)(2n−2)⋯2(2n−1)(2n−3)⋯1⋅2π. Evaluate ∫0π/2sin6x dx\displaystyle\int_0^{\pi/2}\sin^6x\,dx∫0π/2sin6xdx.Check Show answer Walk through it step by step Practice more like this Review this concept