CalculusHardNon-Elementary Integration ShareNon-Elementary Integration · Hard problemGiven ∫0∞e−x2 dx=π2\displaystyle\int_0^{\infty}e^{-x^2}\,dx=\dfrac{\sqrt\pi}{2}∫0∞e−x2dx=2π, evaluate ∫0∞x2e−x2 dx\displaystyle\int_0^{\infty}x^2e^{-x^2}\,dx∫0∞x2e−x2dx.Check Show answer Walk through it step by step Practice more like this Review this concept