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CalculusHardNon-Elementary Integration

Non-Elementary Integration · Hard problem

Given ∫0π/2ln⁡(sin⁡x) dx=−π2ln⁡2\displaystyle\int_0^{\pi/2}\ln(\sin x)\,dx=-\dfrac{\pi}{2}\ln 2, evaluate ∫0πln⁡(1−cos⁡x) dx\displaystyle\int_0^{\pi}\ln(1-\cos x)\,dx.