CalculusHardNon-Elementary Integration ShareNon-Elementary Integration · Hard problemLet I(a)=∫0∞e−x2cos(ax) dxI(a)=\displaystyle\int_0^{\infty}e^{-x^2}\cos(ax)\,dxI(a)=∫0∞e−x2cos(ax)dx, so I(0)=π2I(0)=\dfrac{\sqrt\pi}{2}I(0)=2π. By differentiating under the integral sign, find I(2)=∫0∞e−x2cos2x dxI(2)=\displaystyle\int_0^{\infty}e^{-x^2}\cos 2x\,dxI(2)=∫0∞e−x2cos2xdx.Check Show answer Walk through it step by step Practice more like this Review this concept