MathCastle
CalculusHardNon-Elementary Integration

Non-Elementary Integration · Hard problem

Let I(a)=∫0∞e−x2cos⁡(ax) dxI(a)=\displaystyle\int_0^{\infty}e^{-x^2}\cos(ax)\,dx, so I(0)=π2I(0)=\dfrac{\sqrt\pi}{2}. By differentiating under the integral sign, find I(2)=∫0∞e−x2cos⁡2x dxI(2)=\displaystyle\int_0^{\infty}e^{-x^2}\cos 2x\,dx.