CalculusHardNon-Elementary Integration ShareNon-Elementary Integration · Hard problemGiven ∫0∞sinxx dx=π2\displaystyle\int_0^{\infty}\dfrac{\sin x}{x}\,dx=\dfrac{\pi}{2}∫0∞xsinxdx=2π, evaluate ∫0∞x−sinxx3 dx\displaystyle\int_0^{\infty}\dfrac{x-\sin x}{x^3}\,dx∫0∞x3x−sinxdx.Check Show answer Walk through it step by step Practice more like this Review this concept