CalculusChallengeNon-Elementary Integration ShareNon-Elementary Integration · Challenge problemGiven ∫0π/2ln(sinx) dx=−π2ln2\displaystyle\int_0^{\pi/2}\ln(\sin x)\,dx=-\dfrac{\pi}{2}\ln2∫0π/2ln(sinx)dx=−2πln2, evaluate ∫0πxln(cscx) dx\displaystyle\int_0^{\pi}x\ln(\csc x)\,dx∫0πxln(cscx)dx.Check Show answer Walk through it step by step Practice more like this Review this concept