CalculusChallengeNon-Elementary Integration ShareNon-Elementary Integration · Challenge problemLet F(a)=∫0∞e−x 1−cos(ax)x dxF(a)=\displaystyle\int_0^{\infty}e^{-x}\,\dfrac{1-\cos(ax)}{x}\,dxF(a)=∫0∞e−xx1−cos(ax)dx. By differentiating under the integral sign (Feynman's trick), evaluate F(3)=∫0∞e−x 1−cos3xx dxF(3)=\displaystyle\int_0^{\infty}e^{-x}\,\dfrac{1-\cos 3x}{x}\,dxF(3)=∫0∞e−xx1−cos3xdx.Check Show answer Walk through it step by step Practice more like this Review this concept