CalculusChallengeNon-Elementary Integration ShareNon-Elementary Integration · Challenge problemBy considering I(a)=∫01arctan(ax)x1−x2 dxI(a)=\displaystyle\int_0^{1}\dfrac{\arctan(ax)}{x\sqrt{1-x^2}}\,dxI(a)=∫01x1−x2arctan(ax)dx and differentiating with respect to aaa, evaluate ∫01arctanxx1−x2 dx\displaystyle\int_0^{1}\dfrac{\arctan x}{x\sqrt{1-x^2}}\,dx∫01x1−x2arctanxdx.Check Show answer Walk through it step by step Practice more like this Review this concept