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CalculusChallengeNon-Elementary Integration

Non-Elementary Integration · Challenge problem

By considering I(a)=∫01arctan⁡(ax)x1−x2 dxI(a)=\displaystyle\int_0^{1}\dfrac{\arctan(ax)}{x\sqrt{1-x^2}}\,dx and differentiating with respect to aa, evaluate ∫01arctan⁡xx1−x2 dx\displaystyle\int_0^{1}\dfrac{\arctan x}{x\sqrt{1-x^2}}\,dx.