MathCastle
CalculusChallengeNon-Elementary Integration

Non-Elementary Integration · Challenge problem

Given ∫0π/2ln⁡(sin⁡x) dx=−π2ln⁡2\displaystyle\int_0^{\pi/2}\ln(\sin x)\,dx=-\dfrac\pi2\ln2, evaluate ∫0π/2x2sin⁡2x dx\displaystyle\int_0^{\pi/2}\dfrac{x^2}{\sin^2x}\,dx.