Counting & ProbabilitySuperchallengeBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Superchallenge problemEvaluate ∑k=06(−1)k(6k)(20−2k6)\displaystyle\sum_{k=0}^{6}(-1)^k\binom{6}{k}\binom{20-2k}{6}k=0∑6(−1)k(k6)(620−2k).Check Show answer Walk through it step by step Practice more like this Review this concept