Counting & ProbabilitySuperchallengeBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Superchallenge problemEvaluate ∑k=08(−1)k(8k)(20−k12)\displaystyle\sum_{k=0}^{8}(-1)^k\binom{8}{k}\binom{20-k}{12}k=0∑8(−1)k(k8)(1220−k).Check Show answer Walk through it step by step Practice more like this Review this concept