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GeometrySuperchallengeGeometry Essentials

Geometry Essentials · Superchallenge problem

Seven rays OA1,OA2,…,OA7OA_1, OA_2, \ldots, OA_7 leave point OO in that order around it, splitting the full turn into the seven angles ∠A1OA2,∠A2OA3,…,∠A6OA7,∠A7OA1\angle A_1OA_2, \angle A_2OA_3, \ldots, \angle A_6OA_7, \angle A_7OA_1. The bisectors of these seven angles are drawn. The angle between the bisectors of ∠A1OA2\angle A_1OA_2 and ∠A2OA3\angle A_2OA_3 is 52∘52^\circ; going on around OO, the angles between the bisectors of consecutive angles are 52∘,45∘,53∘,65∘,42∘,50∘,53∘52^\circ, 45^\circ, 53^\circ, 65^\circ, 42^\circ, 50^\circ, 53^\circ (the last is between the bisectors of ∠A7OA1\angle A_7OA_1 and ∠A1OA2\angle A_1OA_2). Find m∠A1OA2m\angle A_1OA_2 in degrees.