GeometryMediumGeometry Essentials ShareGeometry Essentials · Medium problemRays OBOBOB and OCOCOC lie in the interior of ∠AOD\angle AOD∠AOD, in that order from AAA to DDD. m∠AOB=2xm\angle AOB = 2xm∠AOB=2x, m∠BOC=3x−4m\angle BOC = 3x-4m∠BOC=3x−4, m∠COD=x+16m\angle COD = x+16m∠COD=x+16, and m∠AOD=90∘m\angle AOD = 90^\circm∠AOD=90∘. Find m∠BOCm\angle BOCm∠BOC.Check Show answer Walk through it step by step Practice more like this Review this concept