GeometryHardGeometry Essentials ShareGeometry Essentials · Hard problemRay OBOBOB lies in the interior of ∠AOC\angle AOC∠AOC, with m∠AOB=(2x+10)∘m\angle AOB=(2x+10)^\circm∠AOB=(2x+10)∘ and m∠BOC=(4x)∘m\angle BOC=(4x)^\circm∠BOC=(4x)∘. Given m∠AOC=94∘m\angle AOC=94^\circm∠AOC=94∘, ray ODODOD bisects ∠BOC\angle BOC∠BOC. Find m∠BODm\angle BODm∠BOD.Check Show answer Walk through it step by step Practice more like this Review this concept