Number TheorySuperchallengeHard Number Theory ShareHard Number Theory · Superchallenge problemEvaluate ∑k=12025⌊1234k2026⌋\displaystyle\sum_{k=1}^{2025} \left\lfloor \dfrac{1234k}{2026} \right\rfloork=1∑2025⌊20261234k⌋.Check Show answer Walk through it step by step Practice more like this Review this concept