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Linear AlgebraHardVector Spaces & Bases

Vector Spaces & Bases · Hard problem

The vector w=(−6,−4,0)\mathbf w = (-6, -4, 0) lies in the span of u=(3,−3,3)\mathbf u = (3, -3, 3) and v=(3,2,0)\mathbf v = (3, 2, 0). Find the scalars a,ba, b with w=au+bv\mathbf w = a\mathbf u + b\mathbf v.