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Linear AlgebraHardVector Spaces & Bases

Vector Spaces & Bases · Hard problem

The vector w=(2,3,1)\mathbf w = (2, 3, 1) lies in the span of u=(0,0,−1)\mathbf u = (0, 0, -1) and v=(−2,−3,1)\mathbf v = (-2, -3, 1). Find the scalars a,ba, b with w=au+bv\mathbf w = a\mathbf u + b\mathbf v.