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Linear AlgebraHardVector Spaces & Bases

Vector Spaces & Bases · Hard problem

The vector w=(3,−3,9)\mathbf w = (3, -3, 9) lies in the span of u=(−3,3,0)\mathbf u = (-3, 3, 0) and v=(−2,2,3)\mathbf v = (-2, 2, 3). Find the scalars a,ba, b with w=au+bv\mathbf w = a\mathbf u + b\mathbf v.