ChallengeChallenge ShareChallenge · Challenge problemLet ω=e2πi/11\omega = e^{2\pi i/11}ω=e2πi/11. What is ∑j=01012−ωj\displaystyle\sum_{j=0}^{10} \frac{1}{2 - \omega^{j}}j=0∑102−ωj1?A112047\dfrac{11}{2047}204711B222047\dfrac{22}{2047}204722C133112047\dfrac{13311}{2047}204713311D112642047\dfrac{11264}{2047}204711264E111111Check Show answer Walk through it step by step Practice more like this