ChallengeChallenge ShareChallenge · Challenge problemLet ω=e2πi/5\omega = e^{2\pi i/5}ω=e2πi/5. What is ∑j=0413−ωj\displaystyle\sum_{j=0}^{4} \frac{1}{3 - \omega^{j}}j=0∑43−ωj1?A5242\dfrac{5}{242}2425B15242\dfrac{15}{242}24215C647242\dfrac{647}{242}242647D555E405242\dfrac{405}{242}242405Check Show answer Walk through it step by step Practice more like this