MathCastle
AIMEChallengeAdvanced Number Theory

Advanced Number Theory · Challenge problem

Find the number of integers nn with 1≤n≤18001 \le n \le 1800 such that n≡3(mod8)n \equiv 3 \pmod{8} and gcd⁡(n,9)=1\gcd(n, 9) = 1.