AIMEChallengeAdvanced Number Theory ShareAdvanced Number Theory · Challenge problemFind the number of integers nnn with 1≤n≤18001 \le n \le 18001≤n≤1800 such that n≡3(mod8)n \equiv 3 \pmod{8}n≡3(mod8) and gcd(n,9)=1\gcd(n, 9) = 1gcd(n,9)=1.Check Show answer Walk through it step by step Practice more like this Review this concept