PrecalculusHardWhy the Formulas Work ShareWhy the Formulas Work · Hard problemEvaluate 11⋅2+12⋅3+⋯+124⋅25\dfrac{1}{1\cdot 2} + \dfrac{1}{2\cdot 3} + \cdots + \dfrac{1}{24\cdot 25}1⋅21+2⋅31+⋯+24⋅251.Express your answer as a common fraction.Check Show answer Walk through it step by step Practice more like this Review this concept