Counting & ProbabilityHardCounting & Probability ShareCounting & Probability · Hard problemEvaluate 1⋅1!+2⋅2!+3⋅3!+⋯+6⋅6!1\cdot 1! + 2\cdot 2! + 3\cdot 3! + \cdots + 6\cdot 6!1⋅1!+2⋅2!+3⋅3!+⋯+6⋅6!.Check Show answer Walk through it step by step Practice more like this Review this concept